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The Erdos-Strauss Conjecture
The Erdos-Strauss Conjecture. The "Erdos-Strauss conjecture" (ESC) is the statement that for any integer n > 1 there are integers a, b, and c with ... |
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Erdős-Straus Conjecture -- from Wolfram MathWorld
A conjecture due to Paul Erdős and E. G. Straus that the Diophantine ... 4/n=1/a+ 1/b+1/c ... Obláth, R. "Sur l'equation diophantienne 4/n=1/x_1+1/x_2+1/x_3 . |
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Chapter 1 : 4/n=1/a+1/b+1/c (Erdös - Strauss Conjecture : D11 ...
Erdös and Strauss conjectured that the Diophantine equation. 4/n=1/a+1/b+1/c. could be solved in positive integers for all n < 1. (still not be solved.) It is checked ... |
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A192787 - OEIS
A192787, Number of distinct solutions of 4/n = 1/a + 1/b + 1/c in positive integers satisfying 1 <= a ... %C The Erdos-Strauss conjecture is that a(n) > 0 for n > 1. |
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Difficulty with the Erdos-Straus Conjecture - Physics Forums
The Erdos-Straus Conjecture proposes that: For n >= 1, 4/n = 1/a + 1/b + 1/c, has postive integer solutions. n = 2k (evens) n = 4k+3 (odds) |
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On the number of solutions to 4/p = 1/n_1 + 1/n_2 + 1/n_3 - What's new
for which the Erdös-Straus conjecture can be verified. Indeed, from the above lemma we see that if {a, b} are coprime and {c} is any odd factor ... |
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Erd\H{o}s-Straus conjecture | planetmath.org
4 n = 1 a + 1 b + 1 c 4 n 1 a 1 b 1 c \frac{4}{n}=\frac{1}{a}+\frac{1}{b}+\frac{1}{c} ...
c 0 a b c 0 |